using the quadratic formula
-4/3 and -0.4
using the quadratic formula -4/3 and -0.4
If that's + 11, the answer is (15y - 11)(y - 1)
5y2 : the only factors are 5y and y Similarly the only factors of 5 are 5 and 1 these figures must be arranged so that their indiviual multiples total 26y: This can only be (5y + 1)(y + 5) So x = -1/5 or -5
The Greatest Common Factor (GCF) is 13.
2(y - 3)(y - 10)
y = 13Method:Starting with375 = 37+26ySubtracting 37 from both sides:375 - 37 = 37 + 26y -37therefore338 = 26yDividing both sides by 26 leaves only a y on the one side of the equal sign338/26 = yand the final answer isy = 13
192y = 26y × 3y
Multiply each item by 10 to give whole numbers then move items to give ay2+by+c=0 3.5y2+2.6y-8.2=4y2-6.9y multiply by 10 35y2 + 26y - 82 = 40y2 -69y subtract 35y2 from both sides 26y - 82=5y2 -69y subtract 26y from both sides -82 = 5y2 - 95y add 82 to each side 0 = 5y2 - 95y +82 or 5y2 - 95y +82 = 0
-8y+9=18y-4Add 8y to both sides.9=26y-4Add 4 to both sides.13=26yDivide 13 by 26.1/2=y or 0.5=y
It's fine. You don't need to worry.
12y3 - 30y2 + 12yFactor out a y:y(12y2 - 30y + 12)Factor out a 6:6y(2y2 -5y + 2)Factor 2y2 - 5y + 26y(2y - 1)(y - 2)
Make the equations contain an equal co-efficient of x: first multiplied by 7 = -14x + 42y = 42 second multiplied by 2 = -14x + 16y = -10 Subtract leaving 26y = 52 y = 2 -2x + 12 = 6 -2x = -6 x = 3 Check these values in the two original equations.