4x - 8 = 0 when x = 2
Substitute this value of x in 16x3 + 4x2 - 144 to give
16*8 + 4*4 - 144 = 128 + 16 - 144 = 144 - 144 = 0
So, by the remainder theorem, (x-2) is a factor of 16x3 + 4x2 - 144
Also, the coeffs are all divisibl by 4 so 4 is also a factor
(x-2) is a factor, 4 is a factor so 4*(x-2) = (4x - 8) is a factor.
16x + 2 - 8 = 16x + 24 implies 16x - 6 = 16x + 24 subtracting 16x from both sides, this implies: -6 = 24 So the equation has no soultions.
8x2 + 16x + 8 = 0
5x2-16x+12 = (5x-6)(x-2) when factored with the help of the quadratic equation formula
sqrt[(16x)4] = (16x)2 = 256x2
The Commutative Property of Addition.
x3 /12 + 16x + c
16x + 2 - 8 = 16x + 24 implies 16x - 6 = 16x + 24 subtracting 16x from both sides, this implies: -6 = 24 So the equation has no soultions.
8x2 + 16x + 8 = 0
5x2-16x+12 = (5x-6)(x-2) when factored with the help of the quadratic equation formula
sqrt[(16x)4] = (16x)2 = 256x2
The Commutative Property of Addition.
[(-16x)12]1/3 = (-16x)4 = 65536x4
The LCM of 12, 16, 24, and 36 is: 144
16x
16x-8x+12 = 78+22 16x-8x = 78+22-12 8x = 88 x = 11
16X + 5
Combining like terms, 16x + 20 = 180 or 16x = 160 so that x = 10