You cannot, unless n is a counter in a program or algorithm for a looping process. In that case, you need to know what the algorithm is doing.
1/100 or 0.01
If: 100*n = 50 Then: n = 0.5 or 1/2
N represents 100
As n increases, the energy increases. Therefore, electron in the shell of n=100 will have highest energy. But the fact is that there isn't any shell with n=100. Also, n can have values starting from 1 and thus n=0 is not possible as well.
Yes. 1% of n is n/100
n/10^2+7-(1)6=40 n/100+7-6=40 n/100+1=40 (100)n/100+1=40(100) n=4,000 Idk, tired.
The expression "100c 1!" refers to the combination of 100 items taken 1 at a time, denoted as "100 choose 1". This can be calculated using the formula for combinations: ( C(n, r) = \frac{n!}{r!(n-r)!} ). For 100 choose 1, it simplifies to ( \frac{100!}{1! \cdot (100-1)!} = \frac{100}{1} = 100 ). Thus, 100c 1! equals 100.
350n=35000 n=35000/350 n=100
n=1 is the the lowest level there is.
N = 0.007.
n = numberTo find 4% of a number...n/100 = 1%n/100 x 4 = 4%
200 + n = 100 + 200200 + n = 300n = 300 - 200n = 100