1 + 6 - 2 = 5
1 + 62 = 63 or 62 + 1 = 63 or 62 +1 63 ===
62
it equals 62
In reverse: 63 - 1 = 2n = 62 62 / 2 = 31 Now as the question: (2 x 31) + 1 = 62 + 1 = 63 Q.E.D.
50=L 10=X 1=I So the answer is LXII or 62.
-5 + 62 = 31(-5 + 6)2 = 1
10 + 10 + 10 + 10 + 10 + 10 + 1 +1 = 62
x*y+8=70 -8 -8 x*y=62 You could do 62*1, but i would go with 31*2.
The four factors of 62 are 1, 2, 31, and 62. The factor pairs of 62 are (1, 62) and (2, 31)
496 just add everything except 248 it'll come with the same answer ' 248' just add them both :)
1, 2, 31, 62
62 x 1/6 = 62 x 0.16667 = 10.33354