62
62 + 1 = 63
it equals 62
In reverse: 63 - 1 = 2n = 62 62 / 2 = 31 Now as the question: (2 x 31) + 1 = 62 + 1 = 63 Q.E.D.
50=L 10=X 1=I So the answer is LXII or 62.
115
-5 + 62 = 31(-5 + 6)2 = 1
10 + 10 + 10 + 10 + 10 + 10 + 1 +1 = 62
The four factors of 62 are 1, 2, 31, and 62. The factor pairs of 62 are (1, 62) and (2, 31)
1, 2, 31, 62
62 can be written as 62/1.
62 x 1/6 = 62 x 0.16667 = 10.33354