isotope
The atomic number of hydrogen is 1
H = hydrogen O = oxygen N = nitrogen Ne = neon Hydrogen is smallest, so H is the answer.
In H-N=N-H are 2 sigma's (-) between N and H,and there are 1 pi bond + 1 sigma (=) between N and N
N/a
they are the isotopes of hydrogen. 1) hydrogen: proton=1 electron=1 neutron=0 2) deutrium: P=1 E=1 N=1 3) trituim: P=1 E=1 N=2 For info tritruim is the only one that has radiation (LIGHT)
1 the Atomic Number of Hydrogen
The atomic number of hydrogen is 1
multiplication is point to point and convolustion is point to multi-point ex multiplication-- s[n]=x[n].h[n] s[0]=[x[0].h[0] s[1]=[x[1].h[1] s[2]=[x[2].h[2] . . . .. s[n-1]=[x[n-1].h[n-1] convollustion s[n]=x[n]*h[n] s[0]=[x[0].h[0]+x[0].h[1]+x[0].h[2]+.......+x[0].h[n-1] s[1]=[x[1].h[0]+x[1].h[1]+x[1].h[2]+.......+x[1].h[n-1] s[2]=[x[2].h[2]+x[2].h[1]+x[2].h[2]+.......+x[2].h[n-1] . . . s[n-1]=[x[n-1].h[0]+x[n-1].h[1]+x[n-1].h[2]+.......+x[n-1].h[n-1].
1 the Atomic Number of Hydrogen
The atomic number of hydrogen is 1
Good question. It's because of the Sun's temperature. H-alpha is the line produced from exciting an electron from n=2 to n=3 level. Note that to be able to absorb H-alpha, you would need to have a hydrogen atom with its electron already in the n=2 excited state! Exciting n=1 to n=2 (Lyman-alpha) takes a lot of energy, much more than n=2 to n=3, and the Sun's photosphere is not hot enough for much of its hydrogen to be in the n=2 excited state. Hotter stars have more hydrogen in the n=2 state, so it is then easy to do the (less energetic) n=2 to n=3 H-alpha absorption. That's why hotter stars like A stars have much stronger H-alpha lines. Note that stars hotter than A stars (O,B) again have weak hydrogen absorption lines, because they are so hot most of their hydrogen is ionized, and again there is not much hydrgoen in the n=2 state to excite.
HNO2, If ON for H: +1. ON for 02: -2 Then (+1) N 2(-2) (+1) N (-4) Therefore Nitrogen's ON is +3.
Hydrogen is an element on the periodic table. Hydrogen is a brinclhof element (Br, I, N, Cl, H, O, F) and as such occurs in pairs (H subscript 2) in its gaseous state.
H = hydrogen O = oxygen N = nitrogen Ne = neon Hydrogen is smallest, so H is the answer.
In H-N=N-H are 2 sigma's (-) between N and H,and there are 1 pi bond + 1 sigma (=) between N and N
N/a
I think: H2CCH2 H H | | C_C | | H H H2NNH2: H-H-:N-N:-H-H Two Nitrogen atoms connected by single bond with a lone pair and 2 Hydrogen atoms at each ends