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What is the difference between multiplication and convolution?

multiplication is point to point and convolustion is point to multi-point ex multiplication-- s[n]=x[n].h[n] s[0]=[x[0].h[0] s[1]=[x[1].h[1] s[2]=[x[2].h[2] . . . .. s[n-1]=[x[n-1].h[n-1] convollustion s[n]=x[n]*h[n] s[0]=[x[0].h[0]+x[0].h[1]+x[0].h[2]+.......+x[0].h[n-1] s[1]=[x[1].h[0]+x[1].h[1]+x[1].h[2]+.......+x[1].h[n-1] s[2]=[x[2].h[2]+x[2].h[1]+x[2].h[2]+.......+x[2].h[n-1] . . . s[n-1]=[x[n-1].h[0]+x[n-1].h[1]+x[n-1].h[2]+.......+x[n-1].h[n-1].


Answer to 1 the A N of H?

1 the Atomic Number of Hydrogen


What is the oxidation number of N2H4?

In N2H4, the oxidation number of nitrogen (N) is -2. Each hydrogen (H) has an oxidation number of +1.


Oxidation number of N in N2H4?

The oxidation number of N in N2H4 is -2. In hydrazine (N2H4), each hydrogen atom has an oxidation number of +1, and the overall molecule has a charge of 0. Since there are two hydrogen atoms for each nitrogen atom, the oxidation number of nitrogen must be -2 to balance the charges.


Ditloid 1 the A N of H?

1 the Atomic Number of Hydrogen


What does the a n of h is 1 stand for?

The atomic number of hydrogen is 1


The A N of H is 1?

The atomic number of hydrogen is 1, indicating that hydrogen has one proton in its nucleus.


Why oxidation number of N in hydrazine is -2?

In hydrazine (N2H4), the oxidation number of N is -2 because hydrogen (H) is more electronegative than nitrogen (N), so each hydrogen contributes +1 to the overall charge of the molecule. Since hydrazine is a neutral molecule, the two nitrogen atoms must have an oxidation number of -2 each to balance the charges.


Why is the H alpha absorption line of hydrogen in the sun relatively weak even though the Sun has abundant hydrogen?

Good question. It's because of the Sun's temperature. H-alpha is the line produced from exciting an electron from n=2 to n=3 level. Note that to be able to absorb H-alpha, you would need to have a hydrogen atom with its electron already in the n=2 excited state! Exciting n=1 to n=2 (Lyman-alpha) takes a lot of energy, much more than n=2 to n=3, and the Sun's photosphere is not hot enough for much of its hydrogen to be in the n=2 excited state. Hotter stars have more hydrogen in the n=2 state, so it is then easy to do the (less energetic) n=2 to n=3 H-alpha absorption. That's why hotter stars like A stars have much stronger H-alpha lines. Note that stars hotter than A stars (O,B) again have weak hydrogen absorption lines, because they are so hot most of their hydrogen is ionized, and again there is not much hydrgoen in the n=2 state to excite.


How many sigma bonds does hnnh have?

In H-N=N-H are 2 sigma's (-) between N and H,and there are 1 pi bond + 1 sigma (=) between N and N


What is the oxidation number for HNO3?

For nitrogen in HNO3 it is '5'. To calculate oxidation numbers. Use oxygen as the stabndard at '-2' -2 x 3 = -6 is the oxygen moiety. Since hydrogen only oxides to '+1' as H^(+). Create a little sum +1 +N - 6 = 0 To balance then N must be '+5'.


Which is smallest atom H or O or N or Ne?

H = hydrogen O = oxygen N = nitrogen Ne = neon Hydrogen is smallest, so H is the answer.