hydrogen is h
The atomic number of hydrogen is 1, indicating that hydrogen has one proton in its nucleus.
In H-N=N-H are 2 sigma's (-) between N and H,and there are 1 pi bond + 1 sigma (=) between N and N
H = hydrogen O = oxygen N = nitrogen Ne = neon Hydrogen is smallest, so H is the answer.
To balance the reaction Ni + C₄H₈N₂O₂ → Ni(C₄H₈N₂O₂)₂, the coefficients would be 1 for Ni and 2 for C₄H₈N₂O₂. This results in the balanced equation: 1 Ni + 2 C₄H₈N₂O₂ → 1 Ni(C₄H₈N₂O₂)₂.
In carbohydrates, the ratio of carbon (C), hydrogen (H), and oxygen (O) atoms is typically 1:2:1. This means for every carbon atom, there are two hydrogen atoms and one oxygen atom. For example, in glucose (C₆H₁₂O₆), this ratio is evident, reflecting the general formula for simple carbohydrates, which is (CH₂O)n, where n represents the number of carbon atoms.
In N2H4, the oxidation number of nitrogen (N) is -2. Each hydrogen (H) has an oxidation number of +1.
multiplication is point to point and convolustion is point to multi-point ex multiplication-- s[n]=x[n].h[n] s[0]=[x[0].h[0] s[1]=[x[1].h[1] s[2]=[x[2].h[2] . . . .. s[n-1]=[x[n-1].h[n-1] convollustion s[n]=x[n]*h[n] s[0]=[x[0].h[0]+x[0].h[1]+x[0].h[2]+.......+x[0].h[n-1] s[1]=[x[1].h[0]+x[1].h[1]+x[1].h[2]+.......+x[1].h[n-1] s[2]=[x[2].h[2]+x[2].h[1]+x[2].h[2]+.......+x[2].h[n-1] . . . s[n-1]=[x[n-1].h[0]+x[n-1].h[1]+x[n-1].h[2]+.......+x[n-1].h[n-1].
1 the Atomic Number of Hydrogen
The oxidation number of N in N2H4 is -2. In hydrazine (N2H4), each hydrogen atom has an oxidation number of +1, and the overall molecule has a charge of 0. Since there are two hydrogen atoms for each nitrogen atom, the oxidation number of nitrogen must be -2 to balance the charges.
1 the Atomic Number of Hydrogen
The atomic number of hydrogen is 1
The atomic number of hydrogen is 1, indicating that hydrogen has one proton in its nucleus.
In hydrazine (N2H4), the oxidation number of N is -2 because hydrogen (H) is more electronegative than nitrogen (N), so each hydrogen contributes +1 to the overall charge of the molecule. Since hydrazine is a neutral molecule, the two nitrogen atoms must have an oxidation number of -2 each to balance the charges.
Good question. It's because of the Sun's temperature. H-alpha is the line produced from exciting an electron from n=2 to n=3 level. Note that to be able to absorb H-alpha, you would need to have a hydrogen atom with its electron already in the n=2 excited state! Exciting n=1 to n=2 (Lyman-alpha) takes a lot of energy, much more than n=2 to n=3, and the Sun's photosphere is not hot enough for much of its hydrogen to be in the n=2 excited state. Hotter stars have more hydrogen in the n=2 state, so it is then easy to do the (less energetic) n=2 to n=3 H-alpha absorption. That's why hotter stars like A stars have much stronger H-alpha lines. Note that stars hotter than A stars (O,B) again have weak hydrogen absorption lines, because they are so hot most of their hydrogen is ionized, and again there is not much hydrgoen in the n=2 state to excite.
In H-N=N-H are 2 sigma's (-) between N and H,and there are 1 pi bond + 1 sigma (=) between N and N
For nitrogen in HNO3 it is '5'. To calculate oxidation numbers. Use oxygen as the stabndard at '-2' -2 x 3 = -6 is the oxygen moiety. Since hydrogen only oxides to '+1' as H^(+). Create a little sum +1 +N - 6 = 0 To balance then N must be '+5'.
H = hydrogen O = oxygen N = nitrogen Ne = neon Hydrogen is smallest, so H is the answer.