Every second number is 2 and others just go up. So it's 6 2 7 2 8 2 9 2 10 (or 1).
The pattern will be +2, +3, +4, +4
i0 = 4; in = in-1 - 3
Homework question: The first numbetr is 4. A rule is multiply by 2 and then subtract 3. What are the first 6 numbers in the pattern
3 4 6 9 13 18...1....2....3....4......5
There are infinitely many possible solutions. A simple one is Un = (n2 - 3n + 8)/2 for n = 1, 2, 3, ...
The pattern will be +2, +3, +4, +4
+2, +3, +2
i0 = 4; in = in-1 - 3
Homework question: The first numbetr is 4. A rule is multiply by 2 and then subtract 3. What are the first 6 numbers in the pattern
3 4 6 9 13 18...1....2....3....4......5
t(n) = 3(n-1) + 1, for n = 1, 2, 3, etc
+3 -3 +4 -3 +5 -3
There are infinitely many possible solutions. A simple one is Un = (n2 - 3n + 8)/2 for n = 1, 2, 3, ...
3 is the answer
+3, -3, +4, -3, +5, -3, (+6, -3, +7, -3...)
Subtract 2 from the previous number. 10-2 = 8 8-2 = 6 6-2 = 4 4-2 = 2
5-30-6-42-7-56-8-72