9+13=22 13-9=4
9 13
9 + 13 = 22
8 and 6 have a difference of 2 and a sum of 14.
The sum of a sequence is given by sum = n/2(2a + (n-1)d) where: n = how many a = first number of sequence d = difference between terms of sequence. For the first 22 odd numbers these are: n = 22 a = 1 d = 2 → sum = 22/2(2×1 + (22 - 1)×2)) = 22² = 484 The sum of the first n odd numbers is always n²: sum = n/2(2×1 + (n-1)2) = n/2(1 + (n-1))×2 = n(n) = n²
The numbers are 22 and 24.
The two numbers are 10 and 2
22 - 12 = 10; 10/2 = 5 = lower number so higher number = 17.
Three
The numbers are 11 and 10
24,26
0.4 and 2.
6 and 4.