2 of each Animal on Noah's Ark
(n+2)/n = 110Multiply each side by 'n':n + 2 = 110nSubtract n from each side:2 = 109nDivide each side by 109:n = 2/109
41
41 - 2n = 2 + n Add 2n to each side: 41 = 2 + 3n Subtract 2 from each side: 39 = 3n Divide each side by 3: 13 = n
180(n-2)/n
The sum of the interior angles is (n-2)*pi radians So each interior angle is (n-2)/n * pi radians
(N/5) x (2) = 1Divide each side of the equation by 2:(N/5) = 0.5Multiply each side by 5 :N = 2.5
(n-2) x 180 = sum of interior angles (n-2) x 180 _________ = each interior angle n
This is weird. Let's think for a minute ... how can half of something be as big as ten of it ?Well, let's go through the algebra anyway:n/2 = 10nMultiply each side by 2:n = 10nSubtract n from each side:0 = 9nDivide each side by 9:0 = n=============================Maybe the question meant: 2/n = 10nIn that case, 2 = 10n2, 5n2 = 1, n = sqrt(0.2) = 0.4472 (rounded)
15-12n=n+2? Do you want to find n? 15=13n+2 (add 12n to each side) 13=13n (subtract 2 from each side) n=1 (divide both sides by 13)
In a polygon with n sides, we have n(n-3)/2 diagonals. In a convex polygon with n sides, you can draw n-3 diagonals from each vertex, but you are counting each one twice you so you need to divide by do. That is why we have n(n-3) divided by 2
The recursion tree for the function t(n) 4t(n/2) n has a branching factor of 4 at each level, with each node representing a subproblem of size n/2. The height of the tree is logn, and the total number of nodes in the tree is O(n).
The oxidation number of Mg in Mg3N2 is +2. Each N has an oxidation number of -3, so for the compound to be neutral, the magnesium atoms must have an oxidation number of +2.