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2x2 - 3x + 7 = 0 doesn't factor neatly. Applying the quadratic formula, we find two imaginary solutions: (3 plus or minus the square root of -47) divided by 4.
x = 0.75 + 1.713913650100261i
x = 0.75 - 1.713913650100261i
where i is the square root of negative 1
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Value of the discriminant for 2x2 - 3x plus 1 equals 0?
The discriminant is 1.
What the x value of 2x square plus 3x plus 9 equals 0?
If 2x2 + 3x + 9 = 0 then x = -0.75 - 1.984i or -0.75 + 1.984i where i is the imaginary square root of -1.
What is the solution set 2x2-3x-1 equals 0?
(-2,-1)
What is the value of the discriminant for the equation 2x2 plus 3x-4 equals 0?
2X2 + 3X - 4 = 0the discriminant is,b2 - 4ac32 - 4(2)(- 4)9 + 32 = 4141 > 1this means there are two real roots to this equation
-4x2 plus 6x plus 40 equals 0?
-4x2 + 6x + 40 = 0 ∴ -2x2 + 3x + 20 = 0 ∴ -2x2 - 8x + 5x + 20 = 0 ∴ -2x(x + 4) + 5(x + 4) = 0 ∴ (5 - 2x)(x + 4) = 0 ∴ x ∈ {5/2, -4}
How do you complete the square 2x2 - 3x plus 1 equals 0?
If: 2x2-3x+1 = 0 Then: x = 1 or x = 1/2
Value of the discriminant for 2x2 - 3x plus 1 equals 0?
The discriminant is 1.
X2 plus 7x equals -2x2 plus 6?
x2+7x=-2x2+6 3x2+7x-6=0 (3x-2)(x+3)=0 3x-2=0 or x+3=0 x=2/3 or x=-3
2x2-3x plus 1 equals 0?
(2x - 1)(x - 1) so x = ½ or 1
2x2 plus 3x plus 1 equals 0?
factorises as (2x + 1)(x + 1) so x = -0.5 or -1
What the x value of 2x square plus 3x plus 9 equals 0?
If 2x2 + 3x + 9 = 0 then x = -0.75 - 1.984i or -0.75 + 1.984i where i is the imaginary square root of -1.
What is the solution set 2x2-3x-1 equals 0?
(-2,-1)
2x2 plus 7x - 15 equals 0?
2x2 + 7x - 15 = 02x2 + 10x - 3x - 15 = 0(2x2 - 3x) + (10x - 15) = 0x(2x - 3) + 5(2x - 3) = 0(2x - 3)(x + 5) = 0(2x - 3) = 0 or (x + 5) = 0x = 3/2 or x = -5
What is the value of the discriminant for the equation 2x2 plus 3x-4 equals 0?
2X2 + 3X - 4 = 0the discriminant is,b2 - 4ac32 - 4(2)(- 4)9 + 32 = 4141 > 1this means there are two real roots to this equation
-4x2 plus 6x plus 40 equals 0?
-4x2 + 6x + 40 = 0 ∴ -2x2 + 3x + 20 = 0 ∴ -2x2 - 8x + 5x + 20 = 0 ∴ -2x(x + 4) + 5(x + 4) = 0 ∴ (5 - 2x)(x + 4) = 0 ∴ x ∈ {5/2, -4}
What is the roots of the equation 2xsquare-3x-4 equals 0?
2x2 -3x - 4 = 0 use the qudratic equation and your answers are 1.137458609 and -2.637458609
Can you put the equation x2 - 5 -4x2 plus 3x equals 0 in the form ax2 plus bx plus c equals 0?
x2-5-4x2+3x = 0 -3x2+3x-5 = 0 or as 3x2-3x+5 = 0
