-4x2 + 6x + 40 = 0
∴ -2x2 + 3x + 20 = 0
∴ -2x2 - 8x + 5x + 20 = 0
∴ -2x(x + 4) + 5(x + 4) = 0
∴ (5 - 2x)(x + 4) = 0
∴ x ∈ {5/2, -4}
Chat with our AI personalities
x3 + 4x2 + 6x + 24 = (x2 + 6)(x + 4)
8x3 + 4x2 + 6x + 3 = 4x2(2x + 1) + 3(2x + 1) = (2x + 1)(4x2 + 3)
10
6x = 32 - 4y and 4y - 8 = 6x so 32 - 4y = 4y - 8 ie 40 = 8y so y = 5 and x = 2
5x2-2x+16=4x2+6x ,or x2-8x+16=0, or x2-2(x)(4)+(4)2=0, or (x-4)2=0, or (x-4)(x-4)=0, or x=4