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Q: What are three consecutive integers whose sum is 126?

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41, 42 and 43

The two even consecutive integers are: 62+64 = 126

The integers are 41, 42 and 43. Also, using consecutive even integers, you find: 40, 42 and 44.

41+42+43=126.

The integers are are 41, 42 and 43.

63+83=126.... hope it helps!

41,42,43

There is no solution. Since 126 is even and two consecutive integers have to be one odd and one even number, an odd and an even number cannot summate to an even number.

Divide 126 by 2 and choose the even numbers on both sides.

41+42+43 = 126

The numbers are 62 and 64 are two consecutive integers that equal 126.

124+125+126=375

The numbers are 41, 42 and 43.

41, 42, 43

:/ We can write it this way: x - 1 + x + x + 1 = 126. 1s cancel out, so we get 3x = 126. 126/3 = 42. Answer: 41, 42, 43.

The numbers are 62 and 64.

The numbers are 125 and 126.

125, 126 and 127.

It's an even number, so it can't be expressed as the sum of two consecutive integers. You can however do: three consecutive integers: 41 + 42 + 43 four consecutive integers: 30 + 31 + 32 + 33 nine consecutive integers: 10 + 11 + 12 + 13 + 14 + 15 + 16 + 17 + 18. twelve consecutive integers: 5 + 6 + 7 + 8 + 9 + 10 + 11 + 12 + 13 + 14 + 15 + 16

There are two consecutive even numbers. The numbers are 62 and 64.

30, 31, 32 and 33

124 + 125 + 126 = 375

The numbers are 40, 42 and 44.

126, 127, 128

They are 41, 42 and 43.