y(5x - 4)(5x + 7)
28y - 16y = 12y.
12y2+1+15y2-10y-18y=27y2-28y+1. contact at saqibahmad81@yahoo.com
x - y = 63y = x + 22you need to solve these equations simultaneously.first get all your x's and y's on the same side.x - y = 63y - x = 22if you add these two equations together, the x's will cancel as one is positive and the other negative.x - y + 3y - x = 22 + 62y = 28y = 14then substitute y is 14 into one of the original equations to find xx - 14 = 6x = 20
First of all, you haven't asked a question. But I'll just grab this tidbit and gambolthrough the meadow with it anyway, as a pleasant springtime lark, tra la.Let's do it your way: The second equation is 6y + x = 3 .I changed my mind. Your suggestion was to solve this for 'y', but it's easier to solve it for 'x' instead, so I've decided to do this MY way after all.Subtract 6y from each side: x = 3 - 6y Bring that along, while we look at the second equation: 5x + 2y = 33 Substitute the exprssion for 'x' that we derived a moment ago: 5(3-6y) + 2y = 33 Eliminate the parentheses: 15 - 30y + 2y = 33 Subtract 15 from each side: -30y + 2y = 18 Combine like terms on the left side: -28y = 18 Divide each side by -28: y = -18/28y = -9/14 . Wonderful ! Substitute this into the second equation: 6(-9/14) + x = 3x = 3 + 54/14 = 3 + 27/7x = 21/7 + 27/7x = 48/7. What delightful numbers! Nothing like obscuring the forest with so many treesthat the class never notices why you brought them there.FYI ... I also tried it your way, on paper, and that doesn't make it any less messy.
4(1 - 4x + 7y)
7(5x + 4y)
It is 14*(3x + 2y)
It is: (y-14)(y-14)
It is: 28y -16y = 12y
It is: 28y -16y = 12y
y(5x - 4)(5x + 7)
28y - 16y = 12y.
12y2+1+15y2-10y-18y=27y2-28y+1. contact at saqibahmad81@yahoo.com
4y^3 + 48y - 28y^2 = 4y(y - 3)(y - 4)
The GCF is 4.
-28y(y-8)