4(1 - 4x + 7y)
D.4(2x - 3)(2x + 1)
X2 - 16X + 15 = 0 (X - 1)(X - 15) = 0 So X -1 = 0 or X - 15 = 0 ie X = 1 or X = 15
4x times 4x equals 16x2.
In the absence of signs I have assumed the term in 16x and 60 are negative: ie x2 - 16x = -60 or x2 - 16x + 60 = 0 Factors of 60 which total -16 are -6 and -10, so (x - 6)(x - 10)
16x = 4 Divide both sides by 16: x = 4/16 x = 1/4
x2-16x+48 = (x-4)(x-12) when factored
To factor the expression (4 + 16x + 28y), we first observe that the coefficients 4, 16, and 28 have a common factor of 4. Factoring out 4 gives us: [ 4(1 + 4x + 7y) ] Thus, the completely factored form of the expression is (4(1 + 4x + 7y)).
16X + 12X all I can see here is factoring out a 4X factor 4X(4 + 3) ---------------
8x2 + 16x + 8 = 0
To factor the equation ( x^3 + 8x^2 + 16x = 0 ), first, rewrite it as ( x^3 + 8x^2 + 16x + 16 = 16 ). By factoring out the common term ( x ), we get ( x(x^2 + 8x + 16) = 0 ). The quadratic ( x^2 + 8x + 16 ) can be factored as ( (x + 4)^2 ). Therefore, the factored form is ( x(x + 4)^2 = 0 ).
The Commutative Property of Addition.
16x + 2 - 8 = 16x + 24 implies 16x - 6 = 16x + 24 subtracting 16x from both sides, this implies: -6 = 24 So the equation has no soultions.
7.5625
5x2-16x+12 = (5x-6)(x-2) when factored with the help of the quadratic equation formula
16x-8x+12 = 78+22 16x-8x = 78+22-12 8x = 88 x = 11
Combining like terms, 16x + 20 = 180 or 16x = 160 so that x = 10
5x2-16x+12 = (5x-6)(x-2) when factored