I only know two them they are, 1 and 2, but there is one more but you will have to find that out your self.
Prime numbers are only divisible by 1 and themselves. Since 3 is not a prime number, any prime number divisible by 3 does not exist. Therefore, the set of prime numbers divisible by 3 is an empty set.
408 = 2 × 2 × 2 × 3 × 17
No prime numbers are divisible by 3. By definition a prime number isn't divisible by anything but itself and 1.
rectify the question first.. if it is prime then how it is possible to divisible by 3 Prime numbers that are divisible by 3 don't exist. It's a contradictio in terminis ;)
75 is not a prime number as it is divisible by 3 and 5. Prime numbers are numbers that are only divisible by 1 and themselves.
Prime numbers are only divisible by 1 and itself... so no prime number can be divisible by the numbers you listed.
There are no prime numbers divisible by 435. 435 is divisible by 3, 5 and 29
57 is divisible by the prime numbers of 3 and 19
No prime numbers can be equal to 33, as 33 is not a prime number. It is divisible by 3. Prime numbers are only divisible by 1 and themselves, and 33 does not meet this criterion.
2 x 2 x 2 x 3 x 17 = 408
No. For example, 9 wouldn't be prime because it is divisible by 3.
Yes. The prime factorization of 75 is 3 x 5 x 5. So 75 is divisible by the two prime numbers 3 and 5.