Multiply length x width x depth to calculate volume (cubic ft) and multiply by number of gallons per cubic foot (7.481) = 4 x 4 x 2 = 32 x 7.481 = 239.392 gallons.
2 feet 6 inches deep
The opposite of deep. In water terms probably 0 - 2 feet?
I believe that would be 2 feet deep, 2 feet wide, and 2 feet long.
The water level in Hanauma Bay is not equal. If we speak generally, it is from 2 feet to 11 feet in places.
none, it is a hole
None(:
We can't be sure - we need another dimension. If the Pool is 20 feet long by 48 feet wide, we need to know how deep it is - a 2 foot deep pool will not hold as much as a 10 foot deep pool. If the pool is not a uniform depth, there are formulae used to determin how much water the pool will hold. Try calling Anthony. Or Esther Williams.
6 1/2 ft minimum
The only way to get the wrinkles out is to empty it. You've got to be kidding about the 1" deep shallow end and 2' deep end - right?
2 meters or 6.5 feet
Assuming 11 feet is the diameter of the tank, the volume will be 11 times pi times 2, in cubic feet. That equals 69.115 cubic feet (rounded to 3 decimals), which equals 517.016 gallons.
180,358.6357766 gallons <-- Best guess