n + 4
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yes
Let n be the number between 4 and 7 then the required expression is written:- 4 < n < 7 The symbol used is a "less than" symbol and the expression is 4 is less than n which is less than 7. When the arrowhead points to the right > then this is called a "greater than" symbol and we could put n > 4 and 7 > n.
l is greater than n
n - 7 > -3 (add 7 to both sides)n -7 + 7 > -3 + 7n > 4Thus, all real numbers greater than 4 satisfy the given inequality.
It depends on what you mean by a number. If n is a positive integer (except for 1), then n^2 is greater than n. If n = 0 or 1, then n and n^2 are equal. If n = 1/2, then n is greater than its square. If n is negative, then n is always less than its square.
Any number that is greater than 14 or less than -14 will have an absolute value greater than 14. Mathematically expressed as if |n| > 14 then n > 14 or n < -14.
No, for any number n greater than zero, the LCM of n and n is n.
It is 1 - 365Cn/365n. This is greater than 0.5 for n greater than or equal to 23.
Take any integer, n, greater than 1.Then (9*n)/(12*n) will be an equivalent fraction.
If l > m and m > n then l > n by the transitive property of inequality.
2n + 6 > 9 → 2n > 3 → n > 1.5 → n could be 2, 3, 4, ... (Assuming n is an integer.)
No. 1.3 is greater tha n 1.22