4a+3a-4 = 10 4a+3a = 10+4 7a = 14 a = 2
3a + 15 = 4a Subtract 3a from both sides 15 = a So a is 15.
12a
4a + 3a = (4 + 3)a = 7a
10a + 3a - 4a = 9a
"a" plus "3a" is equal to 4a. (3a+a=4a). You already have 3 "a's" and then you add another "a."
3a + 4 = 4a - 3 4 = a -3 (subtract 3a from each side) 7 = a (add 3 to both sides) a = 7
7a-17 = 4a+1 7a-4a = 1+17 3a = 18 a = 6
-7a + 3a = -4a
a < -12
4a + 1 - a =19, rewrite your question, 4a + -a + 1 =19, 3a + 1 =19, subtract 1 from each side 3a = 18, divide by 3, a =6
14a - 4a + 5a - 3a = 12a