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Q: 4x squared plus 12x minus 40 divided by x minus 2?

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x - 2

2(x - 3)(x - 3)

8x squared

(12x2 + 18) / (3x2 + 6) = (4x2 + 6) / (x2 + 2)

With the help of the quadratic equation formula

That doesn't factor neatly. Applying the quadratic equation, we find two real solutions: (-2 plus or minus the square root of 5) divided by 3x = 0.07868932583326327x = -1.4120226591665965

4x2+12x = 4x(x+3) when factored

It is x^2 + 12x or x(x + 12).

2(2x-11)(3x+5)

2x(x−6)(x+1)

x(x + 3)(x - 4)

12x and then the squared. (the little two)

(75y - 12x^2) * y = 75y^2 -12x^2y 75y - (12x^2 * y) = 75y -12x^2y

(3x - y+ 2)(3x + y + 2)

2

x2+12x+5 = 3 x2+12x+5-3 = 0 x2+12x+2 = 0

6(x + 1)(x + 1)

2(x + 4)(x + 2)

(2x - 1)(6x + 5)

(x - 8)(x - 4)

(2x - 3)(2x - 3)

9x2...I guess that means 9x squared ? The problem: 9x(squared)+12x+4 Here's the answer: (3x+2)(3x+2) or even more simplified: (3x+2) squared

The answer is (2x^2+3)(4x+1)

-2x3 - 10x2 - 12x = -2x*(x2 + 5x + 6) = -2x*(x + 2)*(x + 3)

2x + 10x - 6 = 12x - 6