2x(x−6)(x+1)
4x(4x^2 + 3x + 1)
The answer is (2x^2+3)(4x+1)
With the help of the quadratic equation formula
4x + 20
2x(x−6)(x+1)
2x(x^2+x-6)
(4x - 3)(16x^2 + 12x + 9)
4x(4x^2 + 3x + 1)
The answer is (2x^2+3)(4x+1)
(x + 4)(x - 2)(x - 2) or (x + 4)(x - 2)2
With the help of the quadratic equation formula
2(2x-11)(3x+5)
4x + 20
That doesn't factor neatly. Applying the quadratic equation, we find two real solutions: (-2 plus or minus the square root of 5) divided by 3x = 0.07868932583326327x = -1.4120226591665965
15
(75y - 12x^2) * y = 75y^2 -12x^2y 75y - (12x^2 * y) = 75y -12x^2y