x^(3) - x^(2) - 12x
'x' is a common fractor ' tsker it out.
Hence
x(x^(2) - x - 12)
Factor inside the brackets /
x(x - 4(x + 3)
Done!!!!!
The answer is (2x^2+3)(4x+1)
2x^(3) - 10x^(2) - 12x '2' and 'x' are common factors , so take them out. Hence 2x(x^(2) - 5x - 6) Factor inside the brackets . 2x(x - 6)(x + 1) Done !!!!
To factor the expression (18x - 12x^3), first, identify the greatest common factor (GCF) of the terms, which is (6x). Factor out (6x) from each term: [ 18x - 12x^3 = 6x(3 - 2x^2). ] The factored form is (6x(3 - 2x^2)).
With the help of the quadratic equation formula
4x + 20
2x(x^2+x-6)
(4x - 3)(16x^2 + 12x + 9)
The answer is (2x^2+3)(4x+1)
2x^(3) - 10x^(2) - 12x '2' and 'x' are common factors , so take them out. Hence 2x(x^(2) - 5x - 6) Factor inside the brackets . 2x(x - 6)(x + 1) Done !!!!
To factor the expression (18x - 12x^3), first, identify the greatest common factor (GCF) of the terms, which is (6x). Factor out (6x) from each term: [ 18x - 12x^3 = 6x(3 - 2x^2). ] The factored form is (6x(3 - 2x^2)).
(x + 4)(x - 2)(x - 2) or (x + 4)(x - 2)2
With the help of the quadratic equation formula
2(2x-11)(3x+5)
4x + 20
That doesn't factor neatly. Applying the quadratic equation, we find two real solutions: (-2 plus or minus the square root of 5) divided by 3x = 0.07868932583326327x = -1.4120226591665965
15
(75y - 12x^2) * y = 75y^2 -12x^2y 75y - (12x^2 * y) = 75y -12x^2y