To find the number, divide 53 by 0.74.
53 / 0.74 = 71.62
So, 53 is 74% of approximately 71.62.
The prime factors of 53 are 1 and 53, as 53 is a prime number itself. The prime factors of 74 are 1, 2, 37, and 74. Prime numbers are numbers greater than 1 that have no positive divisors other than 1 and themselves.
74 percent of 53 is 39.22
Number of neutrons = Mass number - Number of protons = 127 - 53 = 74
The stable isotope of Iodine is 127 atomic weight and atomic number 53. So it has 53 protons and thus also 53 electrons (to balance the positive charge of the protons) . It has 127-53 = 74 neutrons.
An isotope of iodine with 74 neutrons would have a mass number of 53 +74 = 127. Therefore its symbol would be I -127 or 127 C 53. 127 and 53 should be written as superscript and subscript respectively before writing the chemical symbol of iodine when using the later (127 C 53).Ê 53 is the atomic number of iodine.ÊÊÊÊÊÊÊÊÊÊÊÊÊÊÊÊÊÊÊÊÊÊÊÊÊÊÊÊÊÊÊÊÊÊÊÊÊÊÊÊÊÊÊÊÊÊÊÊÊÊÊÊÊÊÊÊÊÊÊÊÊÊÊÊÊÊ
There are varying isotopes of iodine, but typically an iodine atom has 74 neutrons.
74
127 - 53 = 74
I-125 contains 73 neutrons. To calculate the number of protons, electrons, and neutrons in an uncharged isotope, follow these rules: Protons = atomic number Electrons = protons = atomic number Neutrons = atomic mass - protons Iodine is number 53 on the periodic table, so its atomic number is 53. It has 53 protons and 53 electrons. This particular isotope of iodine is I-125. So, it has 125-53=72 neutrons.
Just multiply with .74 or divide by 100 and than multiply with 74.
Iodine has 53 protons and the only stable isotope has 74 neutrons.
Iodine (I) has 53 protons and 74 neutrons.