If you mean: 5f+10 = 10f then the value of f works out as 2
You can calculate a value if you assign a value to variable "x".
#include<iostream> int main() { int var=42; // store the value 42 in a variable named var. return(0); }
There is no variable, and the equation is not valid.
This is an instruction to increment the value of a variable by 1 (in this case, either the variable count or the variable total).
That depends what the value of x is.
It is a variable which can take any value.
Instantiation is creating the instance of the variable/object . While Initialization is to provide the variable with some value. int i; // i is an instance of an integer i=10; //initialised with the value 10
Both ++you and you++ have the same ending result. The variable you is incremented. The difference is that, if you use the combination in a larger expression, then you++ will have the initial value of you, while ++you has the incremented value of you.
A variable is any named value of a specified type that can hold any value of that type, and that can change that value at any time while the name is in scope. A constant is exactly the same as a variable except that its value must be set at the point of instantiation and the given value cannot be altered while the name remains in scope. In other words, a variable is a value that may vary while a constant is a value that always remains the same.
K+1 is as simplified as it gets. Unless you find the value of K. You can't add a variable and number.
And what is the question? - The value of such an expression will depend on the value assigned to the variable, in this case, "t".
ANYTIME. a number is next to a variable it means that number has to be multiplied by the variable. Try writing it out as 30 times x in the equation. Its quite simple just refere to the Order of operations and PEMDAS search around if you are not sure on how to find the value of a variable. Its actually quite simple. Since I infer you are probably doing homework I don't want to go ahead and give you the value so this is the most i can help you.