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8 w p on a c b?

Updated: 10/20/2023
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Name three collinear points that lie in plane p?

a b c, t r w, z p t; any three variables


What is the area of a rectangle with a perimeter of 28 units and a lenght of 8 units?

P = 2L + 2W P/2 = L + W 28/2 = 8 + W 14 = 8 + W 6 = W A = LW A = (8)(6) A = 48 unit2


A bag contain 4 balls 2 balls are drawn at random and are found to be white What is the probability that all balls are white?

it has three cases 1st E1- two balls are whiteE2- three balls are whiteE4-four balls are whiteE4/w= (p(E3)*4C2/4C2)/(P(E1)*2C2/4C2+P(E2)3C2/4C2+P(E3)*4C2/4C2)WHERE-P(E1)=P(E2)=P(E3)=1/3----------------------------------------------------------------------------------------------------2nd opinionLet's say we have 3 boxes with 4 balls each.Box A has 4 white balls.Box B has 3 white balls.Box C has 2 white balls.The probability of drawing 2 W balls from;Box A, P(2W│A)=(4/4)∙(3/3)=1Box B, P(2W│B)=(3/4)∙(2/3)=1/2Box C, P(2W│C)=(2/4)∙(1/3)=1/6Say the probability of picking any of the 3 boxes is the same, we have;P(A)=1/3P(B)=1/3P(C)=1/3Question is, given the event of drawing 2 W balls from a box taken blindlyfrom the 3 choices, what is the probability that the balls came from box A,P(A│2W).Recurring to Bayes Theorem:P(A│2W)=[P(A)P(2W│A)]/[P(A)P(2W│A)+P(B)P(2W│B)+P(C)P(2W│C)]=[(1/3)(1)]/[(1/3)(1)+(1/3)(1/2)+(1/3)(1/6)]=6/10=0.60=60%P(A│2W)=0.60=60%Read more:Solution_to_a_bag_contains_4_balls_Two_balls_are_drawn_at_random_and_are_found_to_be_white_What_is_the_probability_that_all_balls_are_white


A bag contains 4balls two balls are drawn at random and are found to be white what is the probability that all balls are white?

the odds theoretically are almost infinity to 1 as they could be any color. -------------------------------------------------------------------------------------------2nd opinionLet's say we have 3 boxes with 4 balls each.Box A has 4 white balls.Box B has 3 white balls.Box C has 2 white balls.The probability of drawing 2 W balls from;Box A, P(2W│A)=(4/4)∙(3/3)=1Box B, P(2W│B)=(3/4)∙(2/3)=1/2Box C, P(2W│C)=(2/4)∙(1/3)=1/6Say the probability of picking any of the 3 boxes is the same, we have;P(A)=1/3P(B)=1/3P(C)=1/3Question is, given the event of drawing 2 W balls from a box taken blindlyfrom the 3 choices, what is the probability that the balls came from box A,P(A│2W).Recurring to Bayes Theorem:P(A│2W)=[P(A)P(2W│A)]/[P(A)P(2W│A)+P(B)P(2W│B)+P(C)P(2W│C)]=[(1/3)(1)]/[(1/3)(1)+(1/3)(1/2)+(1/3)(1/6)]=6/10=0.60=60%P(A│2W)=0.60=60%Read more:Solution_to_a_bag_contains_4_balls_Two_balls_are_drawn_at_random_and_are_found_to_be_white_What_is_the_probability_that_all_balls_are_white


What capital letters don't have parallel lines?

A b c d g j k l o p q r s t u v w x y.

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What is a234 wpb-w?

W=wrought p=pipe b=bend


The length is 12 more then the width the perimiter is 7 times the width?

It's been a while, but I'll take a stab at this one. Assuming this is a rectangular shape: width = w length = w + 12 perimeter = length + length + width + width As stated above, p = 7w, so: 7w (perimeter) = (w + 12) + (w + 12) + w + w 7w = 4w + 24 (simplifying the above) -4w -4w (getting all the w's on one side) ------------------ 3w = 24 w = 8 Checking our work. Substituting 8 for w: p = 7(8) p = 56 P = (8+12) + (8 + 12) + 8 + 8 p = 20 + 20 + 8 + 8 p = 56


What is the area of a rectangle with a perimeter of 28 units and a lenght of 8 units?

P = 2L + 2W P/2 = L + W 28/2 = 8 + W 14 = 8 + W 6 = W A = LW A = (8)(6) A = 48 unit2


What is astm a234 wpb-w?

W=wrought p=pipe b=bend


What are some nine letter words with 1st letter B and 3rd letter C and 5th letter W?

According to SOWPODS (the combination of Scrabble dictionaries used around the world) there are 8 words with the pattern B-C-W----. That is, nine letter words with 1st letter B and 3rd letter C and 5th letter W. In alphabetical order, they are: backwards backwater backwoods backwords backworks backwraps becowards buckwheat