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Let's assume that the rectangle has length 'l' and width 'w'.

The formula for the area of a rectangle is A = l × w, and the formula for the perimeter (P) of a rectangle is P = 2(l + w).

We're given that the area of the rectangle is 6cm², so:

A = l × w = 6cm²

We're also given that the perimeter of the rectangle is 14cm, so:

P = 2(l + w) = 14cm

We can use the second equation to solve for one of the variables in terms of the other:

l + w = 7

l = 7 - w

Substituting this into the equation for the area, we get:

(7 - w) × w = 6

Expanding the left side of the equation, we get:

7w - w² = 6

Rearranging and factoring, we get:

w² - 7w + 6 = 0

This equation can be factored as:

(w - 1)(w - 6) = 0

So, w = 1 or w = 6.

If w = 1, then l = 7 - w = 6, and the perimeter would be:

P = 2(l + w) = 2(6 + 1) = 14

If w = 6, then l = 7 - w = 1, and the perimeter would still be:

P = 2(l + w) = 2(1 + 6) = 14

Therefore, there are two possible solutions: a rectangle with dimensions 1cm × 6cm, and a rectangle with dimensions 6cm × 1cm.

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