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The perpendicular from O meets AB at P which is the midpoint of AB.

In the right angled triangle OAP, angle P is 90 deg,

OA = radius = 17 cm

and AP = 0.5*AB = 8 cm

So OP2 = OA2 - AP2 = 172 - 82 = 289 - 64 = 225

OP = 15 cm

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Q: AB is a chord of a circle with centre O with radius 17cmIf AB equals 16cm find the distance of O from AB?
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