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It cannot be basic since all alkalis/bases end or have OH (hydroxide) in the equation making this acidic
hello
This reaction doesn't exist.
The chemical name is copper nitrate
The answer is 3 moles of Cu)NO3)2..
NaBr is a salt because it has Na in it CuNo32 may be a nonelectrolyte NH3 is a base KOH is a base CaCl2 may be a nonelectrolyte hope that somewhat helps
CuNO32is not physically, chemically, philosophically, or metaphorically possible, but Copper(II) nitrate is the chemical compound with the formula Cu(NO3)2.
If something being reduced, it loses an oxygen, and if something is being oxidized, it gains an oxygen. The element being reduced is called the oxidizer; the element being oxidized is called the reducer. (just remember, it's called the opposite of what happens to it) In the context of your equation, which i assume to be CuCl2+KNO3-->Cu(NO3)2+2KCl, potassium (or the K) is losing oxygen, which therefore makes that the oxidizer, the one being reduced.
No. In concentrated nitric acid, the reaction produces copper (II) nitrate, nitrogen dioxide (a toxic, brownish colored gas) and water. The reaction is as follows: Cu(s) + 4HNO3(aq) --> Cu(NO3)2(aq) + 2NO(g) + 2H2O(l) In diluted nitric acid, the reaction produces copper (II) nitrate, nitric oxide (NO), and water. The reaction is as follows: 3Cu(s) + 8HNO3(aq) --> 3Cu(NO3)2(aq) + 2NO(g) + 4H2O(l) (Source: www.angelo.edu)