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A 2100 KG car is traveling at 25 meters per second when it crashes into the rear of a 1650 KG car traveling at 21 meters per second in the same direction. With the road covered in ice find velocity.?
Wiki User
∙ 7y ago
Your problem is actually more complicated than it appears on the surface, but it can be greatly simplified if you make certain assumptions. First, we can assume that you're assuming a frictionless system, because you introduce ice, which, although not totally frictionless, is often thought of as such. Second, we are going to have to ignore the energy used to deform the cars. Both cars have kinetic energy, but some of it will be used to deform the vehicles. If we assume a perfectly elastic system, then we can ignore the energy of deformation. Which leaves you with the conservation of momentum. Momentum must be conserved, so the momentum of the conjoined cars must be the same as the sum of the cars' momentums (or if you prefer, momenta) before the crash. Note that momentum is the product of mass and velocity. You should now have enough information and background to solve your problem with simple algebra.
Wiki User
∙ 16y ago
Wiki User
∙ 7y agoThe assumptions here seem to be that friction can be neglected, and that the vehicles stick together after the crash. In that case, you can use conservation of momentum. Calculate the momentum (mass x velocity) for each car, add both up, and divide by the combined mass to get the speed.
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