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Using conservation of energy means that potential energy is being converted into kinetic enegy and you can set the two equations equal.

PE = gmh and KE = 1/2mV2 become

gmh = 1/2mV2

mass can be algebraically eliminated

gh = 1/2V2

(9.8 m/s2)(12 m) = 1/2V2

117.6 = 1/2V2

multiply through by 2

235.2 = v2

take square root both sides

15 meters per second = velocity

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Q: A 2 kg object is dropped from a height of 12 m Using the conservation of energy calculate the speed it has at the end of the 12 m fall?

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