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Using conservation of energy means that potential energy is being converted into kinetic enegy and you can set the two equations equal.

PE = gmh and KE = 1/2mV2 become

gmh = 1/2mV2

mass can be algebraically eliminated

gh = 1/2V2

(9.8 m/s2)(12 m) = 1/2V2

117.6 = 1/2V2

multiply through by 2

235.2 = v2

take square root both sides

15 meters per second = velocity


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โˆ™ 2011-11-06 21:53:10
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Q: A 2 kg object is dropped from a height of 12 m Using the conservation of energy calculate the speed it has at the end of the 12 m fall?
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A dropped ball doesn't bounce back to its starting height how does this situation fit the law of conversation of energy?

According to the scientific law of conservation of energy the energy can be sustained by the bouncy ball indefinitely

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After the car is dropped, it has NO gravitational potential energy.Before it's dropped, you can calculate the potential energy as mgh (mass x gravity x height). You can use 9.8 for gravity.

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