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The specific heat of lead is 0.0305 K cal/kg deg C. The heat absorbed will be 38x(180-26)x0.0305 = 178.5 Kcal = 746.1 K joules

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Q: A 38 kg block of lead is heated from 26 degrees Celsius to 180 degrees Celsius how much heat energy does the block of lead absorb to increase its temperature this much?
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