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A 3 gallon mixture contains one part S and two parts R In order to change it to a mixture containing 25 percent S how much R should be added?
Wiki User
∙ 14y ago
Call the unknown amount of substance R to be added a. The mixture initially contains 1 gallon of S combined with 2 gallons of R. After the addition, the mixture will contain the oiginal 1 gallon of S and (2 + a) gallons of R. In order for the content of S to be 25 % after the mixing, 1 gallon must equal 0.25(1 + 2 + a)gallons, or (1 - 0.75)gallons = (0.25)a, or a = 0.25/0.25 = 1 gallon.
Wiki User
∙ 14y ago
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