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A Line of slope of negative 5 passing through the point 3 and 4?
Wiki User
∙ 14y ago
y=mx + b, where m=slope and b=y intercept.
At the point (3,4) x=3 and y=4. Thus,
4=-5(3) + b
4 = -15 + b
19 = b
Substitution gets us: y = -5x + 19
Wiki User
∙ 14y ago
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17
Through the origin with slope 7?
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It has not got a slope because it's a vertical straight line.
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17
Through the origin with slope 7?
The line passing through the point (0,0) with a slope of 7 would be y=7x.
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you guts are lazy bums now answer your own questions....
How do you write an equation of a line in slope intercept form with a slope of 5 and passing through the point 0 and 6?
It is: y = 5x+6
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It has not got a slope because it's a vertical straight line.
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To find the slope of a line passing through a given pair of points is found by using the point slope formula. Y(2)-Y(1) over x(2) -x(1).
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If the slope is undefined, it is a vertical line. Therefore the equation is x=2.
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Points: (14, 5) and (20, 4) Slope: -1/6
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