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# A ball is thrown horizontally at 20 m s from the top of a cliff 50 meters high How long does it take the ball to reach the ground?

Updated: 9/17/2023 Wiki User

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Q: A ball is thrown horizontally at 20 m s from the top of a cliff 50 meters high How long does it take the ball to reach the ground?
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### A ball is thrown horizontally from a cliff and hits the ground 4 seconds later 40 meters from the base of the cliff?

The ball was thrown horizontally at 10 meters per sec, and the thrower's arm was 78.4 meters above the base of the cliff.

64 METERSA+

10 m/s

### A ball is thrown horizontally at 20 m s from the top of a cliff 50 meters high How far form the base of the cliff does the ball strike the ground?

64 metersIf a ball is thrown horizontally at 20 m/s from the top of a cliff that is 50 meters high, the ball will strike the ground 64 m from the base of the cliff (20m/s x 3.2 s).

### A ball thrown horizontally from a cliff and hits the ground 4 seconds later 40 meters from the base of the cliff How high was the cliff?

If it was thrown horizontally, it had an initial velocity of 10 meters/sec parallel to the ground. (It traveled 40 meters in 4 secs with no acceleration. x=vt) It also took 4 secs to travel vertically. It started with a vertical velocity of 0 m/s. Using x=v0 + (1/2) a t2 a = -g ( Acceleration due to gravity 9.8m/s2) x=0-(1/2)g*16 = -8 * 9.8 = -78.4 m It fell 78.4 meters before coming to a stop.

### A ball is thrown horizontally at 20 from the top of a cliff 50 meters high How far from the base of the cliff does the ball strike the ground?

the time it takes to get to ground is s = 1/2 at^2 where a is gravity acceleration of 9.8 m/s/s and s is 50 meters and t^2 is time squared.Solve for time t = 3.2 secondsThe horizontal distance from base of cliff is h = vt where h is distance and v is velocity = 20 m/sh = 20 x 3.2 = 64 meters

### A ball is thrown horizontally at 20 ms from the top of a cliff 50 meters high. How far from the base of the cliff does the ball strike the ground?

the time it takes to get to ground is s = 1/2 at^2 where a is gravity acceleration of 9.8 m/s/s and s is 50 meters and t^2 is time squared.Solve for time t = 3.2 secondsThe horizontal distance from base of cliff is h = vt where h is distance and v is velocity = 20 m/sh = 20 x 3.2 = 64 meters

### A rock is thrown from a cliff and hits the ground 5 seconds later at a distance of 50 meters from the cliff How high was the cliff?

Assuming you throw the rock horizontally off the cliff it drops down at the acceletrtion of gravity. height= 1/2 gt^2 With g = 9.8 m/sec and t = 5 seconds we have height = (1/2) (9.8)(5)(5) = 122.5 meters notice it has nothing todo with the 50 meter distance, which depends on the horizontal velocity.

### What object exhibit two dimensional?

An object thrown upward at an angle An object that's thrown horizontally off a cliff and allowed to fall

### A ball is thrown horizontally from a cliff at a speed of 9 meters per second What is its speed one second later?

Ignoring air resistance, its horizontal speed is still 9 meters per second, its vertical speed is approx. 9.81 m/s, as the acceleration of gravity is 9.81 meters per second per second.