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A ball is thrown straight up from a platform 5 feet above the ground with an initial velocity of 20 feet per second Write an equation that you can use to find how long the ball was in the air?
Yorokobifai
Height = H0 + V0 T +1/2a T2
H0 = height when released = +5
V0 = velocity when released = 20 up = +20
a = acceleration of gravity = 32.2 down = -32.2
When the ball hits the ground, "Height" = 0
5 + 20 T - 16.1 T2 = 0
Easier . . . 16.1 T2 - 20 T - 5 = 0
Quadratic formula: T = 1/32.2 [ 20 +/- sqrt(400 + 322) ]
T = (20 +/- 26.87) / 32.2
T = -0.213 seconds
T = 1.456 seconds (rounded)
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∙ 12y ago
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