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It's 9.81m/s since vertical acceleration is always constant.

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Q: A ball rolls off a table and falls 80 m to the floor landing with a speed of 4.5 ms What is the magnitude of the acceleration of the ball just before it strikes the ground?
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The distance travelled by an object in a given time is given by:Distance = Speed * TimeAlternatively for an object that is accelerating:Distance = (Speed of object before acceleration is applied * Time) + (0.5 * Acceleration * Time squared)If the object is accelerating from speed zero, the first set of brackets is irrelevant.Also, if the object is falling to the ground, acceleration = 9.81

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