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A boat can travel 24 mi in 3 hr when traveling with a current Against the same current it can travel only 16 mi in 4 hr Find the rate of the current and the rate of he boat in still water?
Wiki User
∙ 13y ago
3B + 3C = 24 (so B + C = 8)
4B - 4C = 16 (so B - C = 4)
Now we can use:
B + C = 8
B - C = 4
Add the equations:
2B = 12
Boat = 6
Subtract the equations:
2C = 4
Current = 2
Check:
With the current, the boat moves down the river at (6+2)=8 mph, or 24 m in 3 h.
Against the current, it moves up the river at (6-2)=4 mph, or 16 m in 4 h.
Wiki User
∙ 13y ago
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