Boats speed = 24 miles per hour.Current speed = 4 miles per hour.
The boat would make no progress.
The speed upstream is B - C where B is the speed of the badge in still water and C is speed of the current The speed downstream is B + C. Velocity = Distance/Time : therefore Time = Distance/Velocity. Time for upstream journey = 6/(B - C) Time for downstream journey = 6/(B + C) BUT Total time for journey = 2 = 6/(B - C) + 6/(B + C) = 12B/(B2 - C2) Therefore 2B2 - 2C2 = 12B : However, B = 8kph so substituting gives, 128 - 2C2 = 96 : 2C2 = 32 : C2 = 16 : C = 4 The speed of the current is 4kph.
The current is approximately 4 mph.
Velocity = Distance ÷ Time.The speed upstream = 300 ÷ 5 = 60kph.The speed downstream = 300 ÷ 2 = 150 kph.The speed upstream equals boat velocity(Vb) minus current velocity(Vc).The speed downstream equals boat velocity (Vb) pluscurrent velocity (Vc).Vb - Vc = 60Vb + Vc = 150 : Adding the two equations together gives :-2Vb = 210 : Vb = 105, therefore Vc = 45The rate of the boat in still water is 105 kph. The rate of the current is 45 kph.
if the boat turns toward the dock without going upstream, it will miss it's mark because the current is pushing the boat downstream.
If the fault is a direct short to ground, the fault current can be high enough to trip the upstream protection.
The current flows at 4 kph.The boat motors at 11 kph.
Call the unknown speed of the current c and the speed of the boat in still water b. When travelling upstream, the net speed of the boat will be b - c and when travelling downstream the net speed of the boat will be b + c. Since b = 4c, the speed upstream will be 3c. The distance upstream is one-half the total travelling distance of 150 km or 75 kilometers. Distance travelled = speed X time at speed, so that upstream time = 75/3c, downstream time = 75/5c, and the sum of these is the total time stated to be 8 hours. Thus 75/3c + 75/5c = 8. Multiplying both sides by 15c yields 75(5 +3) = 120c, or c = (8 X 75)/120 = 5 kilometers per hour.
Since the distance downstream (with the current) equals the distance upstream (against the current), and if we: Let B stand for the speed (rate in mph) of the boat in still water, and using the formula rate X time = distance, the equation will be: (B+7) x 3 = (B-7) x 5 3B + 21 = 5B - 35 56 = 2B B = 28 mph Traveling downstream, the current will cause the boat to go faster so the 7 mph current is added to the boat's still water speed. Traveling upsteam the current slows or decreases the boat's rate so the current's speed is subtracted from the boat's still water speed.
Let the velocity in still water be V and the current be U. The net velocity upstream (against the current) is 20/6 = V - U . The net velocity downstream is ,18/4 = V + U. Add the equations to get 7.83 = 2V . Subtract the equations to get, 1.17 = 2U. So, V= 3.91 and U = .58
the upstream of a pipe is its inlet and the downstream is its outlet ****if your talking about broadband/internet speed*****downstream is taking information from the internet.(downloading) upstream is putting info on the internet uploading
180m