Acceleration = (change in speed) / (time for the change)
3 = (30) / (time)
3 x (time) = 30
time = 30/3 = 10 seconds
IF your question accelerates towards me at 6megabytes per second then how long will it take me to answer(deccelerate) it if my current velocity is 299.996 miles per second.
I am assuming the initial speed is 6.2 m/s Let upward motion be positive! Gravity decreases the speed by 9.8 m/s each second Acceleration due to gravity = -9.8 m/s each second (negative because gravity accelerates objects downward) Find time to reach the top of the path! Final velocity at the top = 0 m/s Initial velocity = 6.2 m/s Final velocity = Initial velocity + acceleration * time Time - = (final velocity - initial velocity) ÷ acceleration Time = (0 - 6.2) ÷ -9.8 = 0.633 seconds (to reach top) The path is symmetrical. 0.633 seconds to reach top and 0.633 seconds to reach glove again. Total time = 12.66 seconds
Speed=15t + 10 The 15t accounts for acceleration, while the initial velocity of 10 is accounted for by +10. As such, the amount of time (t) for the car to reach 20m/s is 2/3s.
How long will depend on the velocity. The closest star would be 4.24 light years away
From my knoledge only a few seconds - minutes because of the high velocity heading down on earth
It accelerates as long as the force is applied, and after that it continues at a uniform speed and direction.
Yes. Not just a skydiver; anything that falls long enough will eventually reach "terminal velocity", which means that it will continue falling at a constant speed, because the force of gravity and the force of air resistance are in balance.
radius and rpm is not enough you need to know changes in speed over time, so you need to measure how long it takes from "0" velocity to reach maximum velocity
The objective is to calculate the final velocity of 22.8m/s. We can use the formula v = u+at v is th final velocity u is the initial velocity which is equal to 0 in this case a=9.8m/s2( given) t is the time for achieving the final velocity 22.8 = 0+9.8 t t=22.8/9.8 t=2.3 seconds
No. It means how far you went AND how long it took to get there. Velocity = displacement (how far and which direction) / time (how long it took to get there)
It affects the time taken to reach the ground because the larger the area of the parachute the slower its velocity will be and consequently changes how long it takes to reach the ground. The larger parachutes will obtain far more air then smaller parachutes and have more air resistance and drag force.
It accelerates as long as the force is applied, and after that it continues at a uniform speed and direction.