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126km/h /3.6 = 35 m/s

deceleration equals

a = v2/ 2s

352 / (2 x 200) = 3.0625 m/s2

a = dV/dT rearranged dT = dV/a

35/ 3.0625 = 11.43 seconds

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Q: A car moving along a straight highway speed of 126 km per hour is brought to a stop within a distance of 200m what is the retardation of the car and how long does it take for the car to stop?
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