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A certain projectil is launched with an initial speed Vo At its highest poin its speed is Vo divided by 6 What was the launch angle?
Wiki User
∙ 14y ago
(As usual when working with this subject, we'll assume zero air resistance.)
When the projectile is launched, the horizontal component of its velocity is V0cos(A).
At its highest point, its vertical speed is zero; all of its speed is horizontal,
and equal to the horizontal speed it had coming out of the muzzle.
V0/6 = V0cos(A)
cos(A) = 1/6
A = cos-1(1/6) = 80.4 degrees (rounded)
Wiki User
∙ 14y ago
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