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x+y=110

.53x+.97y=.65*110

x=110-y

.53(110-y)+.97y=.65*110

.53*110-.53y+.97y=.65*110

.97y-.53y=(.65-.53)*110

.44y=.12*110

y=.12*110/.44 = 30 ml

x=110-30 = 80 ml

So, you need 80 ml of the 53% solution and 30 ml of the 97% solution.

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Let x be the volume of the 53% solution and y be the volume of the 97% solution. The total volume will be x + y = 110 ml. The equation for the concentration is 0.53x + 0.97y = 0.65(110). Solving these two equations simultaneously gives x = 50 ml of the 53% solution and y = 60 ml of the 97% solution.

Q: A chemist needs 110 milliliters of a 65 percent solution but has only 53 percent and 97 percent solutions available Find how many milliliters of each that should be mixed to get the desired solution?

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I don't know, I suppose we have to ask a chemist.

Each should be 70

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nvm figured the answer out it's 70 ml of 75% ; 20 ml of 84%

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