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y=.12*110/.44 = 30 ml

x=110-30 = 80 ml

So, you need 80 ml of the 53% solution and 30 ml of the 97% solution.

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βˆ™ 2010-03-28 01:24:24
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Q: A chemist needs 110 milliliters of a 65 percent solution but has only 53 percent and 97 percent solutions available Find how many milliliters of each that should be mixed to get the desired solution?
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