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Q: A chemist needs 110 milliliters of a 65 percent solution but has only 53 percent and 97 percent solutions available Find how many milliliters of each that should be mixed to get the desired solution?

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You will need more data about all densities (in kg/Litre)and you must be sure of using mass% = (g solute)/(100 g solution)Solve two equations for both X and Y:4*d50*50 = X*d20*20 + Y*d70*70 (based on salt mass balance in diff. sol'n.)4*d50 = X*d20 + Y*d70 (based on solutions mass balance)In which:dm = density of the 'm'% salt solution in kg/Litre)X and Y = volume of the 20% and 70% salt solutions respectively

I don't know, I suppose we have to ask a chemist.

Benedict solution, or Benedict's reagent, is named for the American chemist Stanley Rossiter Benedict (1884-1936).

50 liters

Dilute

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33ml

Let v be the capacity in milliliters of the 75% solution required then (90 - v) is the required capacity of the 84% solution needed. 75/100v + 84/100(90 - v) = 77/100 x 90 75v + 84(90 - v) = 77 x 90 75v + 7560 - 84v = 6930 9v = 7560 - 6930 = 630 v = 70 : therefore (90 - v) = 20 The mixed solution requires 70ml of the 75% solution and 20ml of the 84% solution to create 90ml of 77% solution.

nvm figured the answer out it's 70 ml of 75% ; 20 ml of 84%

some liquid volumes are not additive, leading to potentially confusing final solution volumes.

For a detailed answer visit: algebra.com/algebra/homework/word/mixtures/Mixture_Word_Problems.faq.question.786696.html

Become a chemist, or hire one.

Minoxidil topical solution is available in India. CIPLA makes it in the name Tugain and Dr. Reddy's lab makes it under a brand called Mintop. Both these generic versions are available in chemist shops without a prescription as they are OTC formulations.

little solvent and much solute r.s.c

Stanley Rottiser Benedict, an American chemist

30 liters of a 10 % solution of fertilizer has .1(30) = 3 liters of fertilizer 1 liter of 30% solution has .3 liter of fertilizer 10 liters of 30% solution has 3 liters of fertilizer so, the chemist needs 10 liters of the 30% solution and 20 liters of water to make 30 liters of a 10% solution.

You will need more data about all densities (in kg/Litre)and you must be sure of using mass% = (g solute)/(100 g solution)Solve two equations for both X and Y:4*d50*50 = X*d20*20 + Y*d70*70 (based on salt mass balance in diff. sol'n.)4*d50 = X*d20 + Y*d70 (based on solutions mass balance)In which:dm = density of the 'm'% salt solution in kg/Litre)X and Y = volume of the 20% and 70% salt solutions respectively

0.5 ml or 1/2

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