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A druggist has a 6 solution and also a 15 solution of a certain medicinehow much of the stronger solution must be add to a liter of the weaker to obtain a 10 solution?
Wiki User
∙ 15y ago
The answer is 0.8 L: Let's think of a '6/15 solution' as meaning 6/15 grams per litre, and the solution we're trying to obtain is 10 grams/litre. In our final solution, we'll have 6 grams resulting from the one litre of weaker solution, and 15v grams from the stronger (where v is the volume of stronger added). Deviding this total mass by the total volume of the solution, we arrive at the wanted concentration of 10 grams/litre. Algebraicly: (15v + 6)/(1+v) litres = 10 15v + 6 = 10 + 10v 5v = 4 v = 4/5 = 0.8 L Hope this helps.
Wiki User
∙ 15y ago
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