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d = a - 2bc
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∙ 2010-05-25 12:27:15This answer is:
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Which of these formulas is correctly rewritten from the original formula to solve for d a equals 2bc plus d?
d=a-2bc
Which of these formulas is correctly rewritten from a equals 2bc plus d to solve for b?
(a-d)/2c=b
Which of these formulas is correctly rewritten from the original formula to solve for b a equals 2bc plus d?
If a=2bc+db= (a - d) / 2c If a=2b+c b=1/2(a-c)
A equals 2bc - d what is the formula to solve for c?
Type your answer here... a = 2bc-d add d to both sides a + d = 2bc divide both sides by 2b (a+d)/2b = c
Which of these formulas is correctly rewritten to solve for d?
a+2bc + d is d= a - 2bc
A equals 2bc - d how do you rewrite the original formula to solve for c?
A = 2bc - dAdd 'd' to each side of the equation:A + d = 2bcDivide each side by 2b :(A + d)/2b = c
What formula is correctly rewritten from the original formula a 2bc d to solve for d?
d = a - 2bc
Which of these formulas is correctly rewritten from the original formula to solve for c if a equals 2bc - d?
(a+d)/2b=c
Which of these formulas is correctly rewritten from the original formula to solve for c a equals 2bc - d?
c= (a+d) / 2b
What formula is correctly rewritten from the original formula to solve for d?
d = a - 2bc
How do you solve a equals b plus c plus d solve for c?
If: a = b+c+d Then: c = a-b-d
Factor this expression 4ac plus 2ad plus 2bc plus bd?
4ac + 2ad + 2bc +bd = 2a*(2c + d) + b*(2c + d) = (2c + d)*(2a + b)
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