to solve ab=c+a for a:Divide both sides by b, so:a= (c+a)/b
b= 1/2 (a - c)
the answer is a
A.
A=0 b=0 c=0
If: a = 2b+c Then: a-c = 2b And: b = (a-c)/2
to solve ab=c+a for a:Divide both sides by b, so:a= (c+a)/b
p=b+3a+c p-3a-c=b+3a-3a+c-c p-3a-c=b b=p-3a-c
b= 1/2 (a - c)
a= (+a) or a= (-) b= 2a b= 2a c= (-a) c= (+a)
the answer is a
Because there is no way to define the divisors, the equations cannot be evaluated.
A.
a=24 b=16 c=18
A=0 b=0 c=0
b + b + b + c + c + c + c = 3b + 4c
a = 20 b = 60 c = 100