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velocity = distance / time There are also some formulae involving acceleration; for example, in the case of constant acceleration: velocity = initial velocity + acceleration x time If the acceleration is not constant, an integral is used instead.
It was 6 radians per second. Angular acceleration = -3 radians per second2 Initial angular velocity = 6 radians per second. Final angular velocity = zero. Average angular velocity = 3 radians per second. Angular displacement in 2 seconds = 3 x 2 = 6 radians.
Assuming constant acceleration: distance = v(0) t + (1/2) a t squared Where v(0) is the initial velocity.
You can use the formula for distance covered:distance = (initial velocity) x (time) + (1/2) (acceleration) (time squared) Solve for time. This assumes constant acceleration, by the way. If you assume that the initial velocity is zero, then you can omit the first term on the right. This makes the equation especially easy to solve.
If you have an initial and final velocity and time you can figure it out with this equation, Vf squared=Vi squared1/2a(t squared) If you don't have those you cannot find acceleration. However the acceleration on Earth is a constant -9.81
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If, as you say, its acceleration is "constant", then the average is exactly equal to that constant.
velocity = distance / time There are also some formulae involving acceleration; for example, in the case of constant acceleration: velocity = initial velocity + acceleration x time If the acceleration is not constant, an integral is used instead.
If you have a particle with constant acceleration, and you add the initial and final velocities and then divide them by two, what you get is the average velocity of the particle in that period of time.
Angular acceleration is got by the expression alpha = {(final angular velocity)2 - (initial ang velocity)2} / 2 theta. final is 50 and initial is 100 rad/s. Theta is 50 x 2pi radian Therefore required alpha = -50 x 150/200 pi = -75/2pi radian/s2 Negative sign indicates that the rotation is decelrated.
Is this a question? or a statement that you are unsure of? Well anyways, this would be correct if acceleration was a constant but if acceleration is not a constant, the (not-constant) acceleration would change the rate of velocity and thus that statement/question would be false.
To find acceleration, you take Vi [Initial Velocity] and you subtract if from Vf [Final Velocity.] (Vi - Vf) If they Vi and Vf are already given, you take the two givens and you subtract them from each other. Vi minus Vf. Do not do Vf minus Vi or it will be wrong. After you do that, you divide your answer from T [Time] (Vi - Vf) a= _____ t Once you get your answer, that will be your acceleration.
I'm assuming you are not talking about constant acceleration, which in itself iscontinuous. If you are talking about constant (meaning it's just a number, and not a function itself) acceleration, than just use the formula:v = i + at, wherev = velocity, i = initial velocity, a = acceleration, and t = timeOtherwise, you need to have some calculus knowledge. A velocity function is just the antiderivative (integral) of an acceleration function.Say, acceleration was given as:a = 2ttake the integral of thatv =∫ 2t dt = (2/2)t2+c =t2+cIn this case, the c is the initial velocity.Example:An object moves with an acceleration determined by a=t+3 (in m/s^2). Find the velocity of the object after 10 seconds have passed, given that the object has an initial velocity of 2 m/s.a = t + 3v =∫( t + 3) dt = (1/2)t2 + 3t + c, with c being initial velocityv(10 seconds) = (1/2)(10)2 + 3(10) + (2) = 82 m/s
zero because the initial and final velocity is constant . so,difference bet. final velocity and initial velocity is zero
Yes, sort of. At least, that's the units used. The actual definition of acceleration is: a = dv/dt In other words, the rate at which velocity changes. In the case of constant acceleration, that would be equal to a change in velocity, divided by the time interval during which this change takes place. In the case of non-constant acceleration, the acceleration, or rate of change of velocity, can of course change from one moment to another.
Wf - Wi = a*t, where Wi and Wf are the initial and final angular velocities, respectively, a is the angular acceleration, and t is time. So, a*t = 15.4 rad/s - 8.5 rad/s = 6.9 rad/s, thus a = 6.9 rad/s / 5.2 s = 1.3 rad/s2.
It is correct only if the object in question is subject to a constant acceleration.