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The distance covered during time ' T ' seconds under constant acceleration is

D = V0T + 1/2 A T2

D = the distance

V0 = speed at the beginning of the time T

A = acceleration during the time T

In this question, V0 = 0, T = 1.895, and A = acceleration of gravity = 9.8 m/s2.

D = 0 + (1/2) (9.8) (1.895)2 = 17.6 meters (57.8 feet) (rounded)

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Q: A girl drops a rock from the edge of a cliff and observes that it strikes the bottom 1.895 s later How high is the cliff?
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