A regular hexagon can be divided into 6 equilateral triangles by drawing diagonals between opposite vertices, if that helps.
A hexagon (six-sided polygon) can be divided into 4 triangles by drawing all of the diagonals from one vertex (only three lines can be drawn in this case, since each vertex already connects to two others on the edges of the form). If you instead drew lines from the center to each vertex, you would get 6 triangles.
The three major diagonals in an ordinary hexagon do not intersect at the same point. Therefore, in such a hexagon, the diagonals form 111 triangles.
A hexagon (six-sided polygon) can be divided into 4 triangles by drawing all of the diagonals from one vertex (only three lines can be drawn in this case, since each vertex already connects to two others on the edges of the form). If you instead drew lines from the center to each vertex, you would get 6 triangles.
18
The answer would be 18.
by drawing them
6-2 = 4 triangles
A hexagon has 9 diagonals
110.Improved Answer:-It is 4
4.
There are 9 diagonals in any hexagon!The hexagon does not have to be regular.