18
4.
The three major diagonals in an ordinary hexagon do not intersect at the same point. Therefore, in such a hexagon, the diagonals form 111 triangles.
A square
A hexagon (six-sided polygon) can be divided into 4 triangles by drawing all of the diagonals from one vertex (only three lines can be drawn in this case, since each vertex already connects to two others on the edges of the form). If you instead drew lines from the center to each vertex, you would get 6 triangles.
Parallelograms of any form, a square, a rectangle, and a rhombus are just special parallelograms so all will form 2 pairs of isosceles triangles when a diagonal is drawn.
The answer would be 18.
4.
The three major diagonals in an ordinary hexagon do not intersect at the same point. Therefore, in such a hexagon, the diagonals form 111 triangles.
Either 12,14,16,or18 I think 18. * * * * * The correct answers is 4. You can draw only 3 diagonals from one vertex.
4
Five of them
Look at it the other way. Draw a hexagon, and draw two horizontal lines, in each case from one vertex to another one. That way you'll see how to divide the hexagon into a rectangle (not necessarily a square), and two triangles - which, of course, you can combine again to form the hexagon.
A square
A hexagon (six-sided polygon) can be divided into 4 triangles by drawing all of the diagonals from one vertex (only three lines can be drawn in this case, since each vertex already connects to two others on the edges of the form). If you instead drew lines from the center to each vertex, you would get 6 triangles.
18
right triangles and
potato