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A jar contains 8 red marbles 9 blue marbles and 6 green marbles Two marbles are picked at random What is the probability that one is green and one is blue?
Mechele66
Without replacement:
P(one green and one blue) = P(drawing green then blue) + P(drawing blue then green)
= (6/23)(9/22) + (9/23)(6/22) = 104/506 = 52/253
With replacement:
P(one green and one blue) = P(green)*P(blue) = (6/23)(9/23) = 54/529
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∙ 13y ago
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