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If h is vertical height, b=horizontal distance from wall to bottom of ladder and l=lenght of ladder,we can say lsquared = hsquared + b squared.

Now differentiate w.r.t. time t.

2l*dl/dt= 2h* dh/dt + 2b*db/dt =0

However this solution doesn't give exactly the same answer when one solves the problem geometrically or using simple pythagorus.

For example ,if l=20m and b=12 m and h=16m and db/dt is 2m/s, I calculate dh/dt as !.5 m/s using calculus but 1.717 m/s using geometry or straight Pythagorus. Where is the fallasy inthe method using calculus?

Ray Bevan

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Q: A ladder long rests against a vertical wall If the top of the ladder slides down at a rate of how fast is the bottom of the ladder sliding away when the bottom of the ladder is away from the wall?
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